A man’s age is three times that of his son, and in twelve years he w

1.	A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
Answer» Let present age of the son = x years present age of the man = 3x years In 12 years : Son’s age will be = (x + 12) years The man’s age will be = (3x + 12) years According to the statement : 3x + 12 = 2(x + 12) => 3x + 12 = 2x + 24 => 3x – 2x = 24 – 12 => x = 12 3x = 3 x 12 = 36 Hence, present age of the man = 36 years Present age of the son = 12 years.

A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.

Answer»

Let present age of the son = x years

present age of the man = 3x years In 12 years :

Son’s age will be = (x + 12) years

The man’s age will be = (3x + 12) years

According to the statement :

3x + 12 = 2(x + 12)

=> 3x + 12 = 2x + 24

=> 3x – 2x = 24 – 12

=> x = 12

3x = 3 x 12 = 36

Hence, present age of the man = 36 years

Present age of the son = 12 years.