A marble block of mass 2 kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g = 10ms^(-2))

A marble block of mass 2 kg lying on ice when given a velocity of 6ms^

1.	A marble block of mass 2 kg lying on ice when given a velocity of 6ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g = 10ms^(-2))
Answer» 0.02 0.03 0.06 0.01 Solution :`v=u+at, a=mu_(K)G`