A marble block of mass 2 kg lying on ice when given a velocity of 6 ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g=10 ms^(-2))

A marble block of mass 2 kg lying on ice when given a velocity of 6 ms

1.	A marble block of mass 2 kg lying on ice when given a velocity of 6 ms^(-1) is stopped by friction in 10 s. Then the coefficient of friction is (g=10 ms^(-2))
Answer» `0.02` `0.03` `0.06` `0.01` ANSWER :C