A mass is whirled in a circular path with constant angular velocity and its angular momentum is L.If the string is now halved keeping the angular velocity the same, the angular momentum is

A mass is whirled in a circular path with constant angular velocity an

1.	A mass is whirled in a circular path with constant angular velocity and its angular momentum is L.If the string is now halved keeping the angular velocity the same, the angular momentum is
Answer» `(L)/(4)` `(L)/(2)` L 2L Solution :We know that angular momentum `L=Mr^(2) omega` Here, MI and ca are constants `:. L prop R^(2)` If `(r)/(2)` becomes angular momentum becomes `(1)/(4)` th of its INITIAL value.