A mass is whirled in a circular path with constant angular velocity an

1.	A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is –(a) \(\frac{L}{4}\)(b) \(\frac{L}{2}\)(c) L (d) 2L
Answer» Correct answer is (a) \(\frac{L}{4}\) We know that angular momentum L = Mr² Here, m and co are constants L \(a\) r² If r becomes \(\frac{r}{2}\) angular momentum becomes \(\frac{1}{4}\) th of its initial value.

A mass is whirled in a circular path with constant angular velocity and its angular momentum is L. If the string is now halved keeping the angular velocity the same, the angular momentum is –(a) \(\frac{L}{4}\)(b) \(\frac{L}{2}\)(c) L (d) 2L

Answer»

Correct answer is (a) \(\frac{L}{4}\)

We know that

angular momentum L = Mr²

Here, m and co are constants L \(a\) r²

If r becomes \(\frac{r}{2}\) angular momentum becomes \(\frac{1}{4}\) th of its initial value.