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A mass m=8kg is attached to a spring as shown in figure and held in position so that the spring remains unstretched. The spring constant is 200 N/m. The mass m is then released and begins to undergo small oscillations. Find themaximum velocity of the mass (g=10m//s^(2)) |
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Answer» Solution :Mean position will be at K,X=MG or `x=(mg)/k=(8xx10)/200=2/5=0.4m` This is also the AMPLITUDE of oscillation i.e. A=0.4m Now `v_("max")=A omega=Asqrt(k/m)=(0.4)SQRT(200/8)=2m//s`
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