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A mass m =8kg is attached to a spring as shown in figure and held in position so that the spring remains unstretched. The spring constant is 200 N/m. The mass m is then released and begins to undergo small oscillations. Find the maximum velocity of the mass (g =10m//s^2) |
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Answer» SOLUTION :Mean position will be at k. x = mg or `x= (mg)/(k) = (8xx10)/(200) =2/5 =0.4m` This is ALSO the amplitude of OSCILLATION i.e. , A=0.4 m Now `v_("max") = A omega = Asqrt(k/m) = (0.4) SQRT((200)/(8)) = 2m//s` |
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