A mass M attached to a horixontal spring executes SHM with an amplitude A_(1) . When mass M passes through its mean position a smaller mass m is placed over it and both of them move together with amplitude A_(2). The ratio of ((A_(1))/(A_(2))) is

A mass M attached to a horixontal spring executes SHM with an amplitud

1.	A mass M attached to a horixontal spring executes SHM with an amplitude A_(1) . When mass M passes through its mean position a smaller mass m is placed over it and both of them move together with amplitude A_(2). The ratio of ((A_(1))/(A_(2))) is
Answer» Solution :`T_(1)= 2pisqrt((M)/(K)), T_(2)= 2pisqrt(((m+M))/(k))` Using law of conservation of linear MOMENTUM `MV_(1)= (m+M)V_(2)` `M(A_(1)omega_(1))= (m+M)(A_(2)omega_(2))` `(A_(1))/(A_(2))= ((m+M))/(M)(omega_(2))/(omega_(1))= ((m+M))/(M)sqrt((k)/(m+M)).sqrt((M)/(k))= sqrt(((m+M))/(M))`