InterviewSolution
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InterviewSolution
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A mass `M`, attached to a horizontal spring, excutes `SHM` with a amplitude `A_(1)`. When the mass `M` passes through its mean position then a smaller mass `m` is placed over it and both of them move together with amplitude `A_(2)`, the ratio of `((A_(1))/(A_(2)))` is :A. `(M)/(M + m)`B. `(M + m)/(M)`C. `((M)/(M + m))^(1//2)`D. `((M + m)/(M))^(1//2)` |
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Answer» Correct Answer - D `C.O.L.M.` `MV_(max) = (m + M)V_("new") , V_(max) = A_(1)omega_(1)` `V_("new") = (MV_(max))/((m + M))` Now, `V_("new") = A_(2).omega_(2)` `(MA_(1))/((m + M))sqrt((K)/(M)) = A_(2)sqrt((K)/((m + M)))` `A_(2) = A_(1)sqrt((M)/((m + M))), (A_(1))/(A_(2)) = ((m + M)/(M))^(1//2)` |
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