1.

A mass M attched to a horizontal spring executes SHM with an amplitude A_(I). When mass M passes through its mean position a smaller mass m is placed over it and both of them move together with amplitude A_(2). The ratio ((A_(1))/(A_(2))) is

Answer»

Solution :`T_(1)=2pisqrt(M/K),T_(2)=2pisqrt(((m+M))/k)`
USING law of conservation of linear momentum `MV_(1)=(m+M)V_(2)`
`M(A_(1)omega_(1))=(m+M)(A_(2)omega_(2))`
`(A_(1))/(A_(2))=((m+M))/M(omega_(2))/(omega_(1))=((m+M))/M sqrt(k/(m+M))sqrt(M/k)=sqrt(((m+M))/M)`


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