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A mass `m` is attached to a spring. The spring is stretched to `x` by a force `F` and refeased. After being released, the mass comes to rest at the initial equilibrium position. The coeffiecient of friction, `mu_(k)` , is `:-` A. `mu_(k)=(2Kx)/(mg)`B. `mu_(k)=(2mg)/(F)`C. `mu_(k)=(F)/(2mg)`D. `mu_(k)=(mg)/(2Kx)` |
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Answer» Correct Answer - C By using work energy theorm, `W=DeltaKE` `Fx-mu_(k)mgx-mu_(k)mgx=0rArrmu_(k)=(F)/(2mg)` |
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