A mass 'm' is revolving in a vertical circle at the end of a string of

1.	A mass 'm' is revolving in a vertical circle at the end of a string of length 1 m. Find difference between the tension at the lowest point and the tension at the highest point.
Answer» T₁ = T₂ = m²₁/r + mg + = m/r (v²₁ + gr) T₂ = L_H = m/r(v²₁ - 2gh) + mg({r - h}/{r}) Since h = 2r We have, T₂ = m/r(v²₁ - 4gr) + mg({r - 2r}/{r}) = m/r(v²₁ - 4gr) - mg Therefore, T₁ - T₂ = m/r(v²₁ + gr) - m/r(v²₁ + 4gr) + mg = 6 mg

A mass 'm' is revolving in a vertical circle at the end of a string of length 1 m. Find difference between the tension at the lowest point and the tension at the highest point.

Answer»

T₁ = T₂ = m²₁/r + mg + = m/r (v²₁ + gr)

T₂ = L_H = m/r(v²₁ - 2gh) + mg({r - h}/{r})

Since h = 2r

We have, T₂ = m/r(v²₁ - 4gr) + mg({r - 2r}/{r})

= m/r(v²₁ - 4gr) - mg

Therefore, T₁ - T₂ = m/r(v²₁ + gr) - m/r(v²₁ + 4gr) + mg

= 6 mg