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A mass m is suspended from the two coupled springs connected in series. The force constant for springs are `k_(1) "and" k_(2).` The time period of the suspended mass will beA. `T = 2pi sqrt((m)/(k_(1)-k_(2)))`B. `T = 2pi sqrt((mk_(1)k_(2))/(k_(1)+k_(2)))`C. `T = 2pi sqrt((m)/(k_(1)+k_(2)))`D. `T = 2pi sqrt((m(k_(1)+k_(2)))/(k_(1)k_(2)))` |
Answer» Correct Answer - D |
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