1.

A mass m is vertically suspended from a spring of negligible mass, the system oscillates with a frequency n. What will be the frequency of the system, if a mass 4m is suspended from the same spring?

Answer»

`(n)/(2)`
2n
`(n)/(4)`
4n

Solution :`n=(1)/(2pi)SQRT((k)/(m)),n.=(1)/(2pi)sqrt((k)/(4m))=(n)/(2)`


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