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| 1. |
A mass m is vertically suspended from a spring of negligible mass, the system oscillates with a frequency n. What will be the frequency of the system, if a mass 4m is suspended from the same spring? |
| Answer» Solution :`n=(1)/(2pi)SQRT((k)/(m)),n.=(1)/(2pi)sqrt((k)/(4m))=(n)/(2)` | |