A mass m moves with a velocity v and collides inelastically with another identical mass at rest. After collision, the first mass moves with velocity v/(sqrt3) in a direction perpendicular to Before collision the initial direction of motion. The speed of the 2^(nd) mass after collision

A mass m moves with a velocity v and collides inelastically with anoth

1.	A mass m moves with a velocity v and collides inelastically with another identical mass at rest. After collision, the first mass moves with velocity v/(sqrt3) in a direction perpendicular to Before collision the initial direction of motion. The speed of the 2^(nd) mass after collision
Answer» `(2v)/(sqrt3)` `v/(sqrt3)` `v` `sqrt(3)v` Solution : In x-direction `mv + 0 = 0 + mv_1 cos theta "" ….(i)` where `v_1` is the velocity of `2^(ND)` MASS. In y-direction `0 = (mv)/(sqrt3) - mv_1 SIN theta` or `mv_1 sin theta = (mv)/(sqrt3) "" …….(ii)` Squaring and adding equs. (i) and (ii), we GET `v_1^2 = v^2 + (v^2)/(3) = (4v^2)/(3) :. v_1 = (2v)/(sqrt3)` .