A mass m moving horizontally (along the x-axis) with velocity v collides and stricks to a mass of 3 m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is

A mass m moving horizontally (along the x-axis) with velocity v collid

1.	A mass m moving horizontally (along the x-axis) with velocity v collides and stricks to a mass of 3 m moving vertically upward (along the y-axis) with velocity 2v. The final velocity of the combination is
Answer» `3/2 V HATI + 1/4 v hatj` `1/4 v hati + 3/2 v hatj` `1/3 v hati + 2/3 v hatj` `2/3 v hati + 1/3 v hatj` SOLUTION : According to conservation of momentum, we GET `m v hati + (3m) 2v hatj= (m + 3 m)v.` where `v.` is the final VELOCITY after collision `v.= 1/4 v hati + 6/4 v hatj = 1/4 v hati + 3/2 v hatj` .