Saved Bookmarks
| 1. |
A mass m of volume `V=10cm^(2)` is tied with a string to the base of a container filled with a liquid of density `(P_(l)=10^(3)kg//m^(3))` as shown in the figure. The container is then accelerated with acceleration `(a_(x)=9m//s^(2))` and `(a_(y)=2m//s^(2))` a shown in the figure. [`g=10((m)/(s^(2)))` acceleration due to gravity] the net buoyancy force acting on the mass isA. 10 NB. 12 NC. 15 ND. 9 N |
|
Answer» Correct Answer - C `F_(B)=sqrt(F_(B//x)^(2)+F_(B//y)^(2))` `F_(B)sqrt([Vrho_(l)(g+a_(y))]^(2)+[Vrho_(l)a_(x)]^(2))` `=10xx10^(-4)xx10^(3)sqrt((12)^(2)+(9)^(2))=15N` |
|