1.

A mass mis suspended from a wire of length L. cross-section A and Young.s modulus Y. It is pulled along the length of the wire and released. Derive an expression for its time period.

Answer»

Solution :`Y=(F)/(A)xx(L)/(x) rArr (F)/(x)=(YA)/(l) rArr K=(F)/(x)=(YA)/(l) rArr T=2pi SQRT((m)/(k)), T=2pi sqrt((m)/((YA)/(l))) rArr T=2pi sqrt((ml)/(YA))`


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