Saved Bookmarks
| 1. |
A mass of 0.5 kg moving with a speed of 1.5 m/s on a horizontal smooth surface collideswith string of force constant 50 N/m . How much maximum compression on the spring will be ? |
|
Answer» `0.5`m ` :. K = PE` ` :. 1/2 mv^(2) =1/2 kx^(2)` ` :. x = sqrt((mv^(2))/k)` ` :. x = sqrt((0.5xx(1.5^(2)))/50)` `:. x = sqrt(((15)^(2))/((100)^(2)))` ` :. x = 0.15 m ` |
|