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A mass of `0.5 kg` moving with a speed of `1.5 m//s` on a horizontal smooth surface, collides with a nearly weightless spring of force constant `k =50 N//m` The maximum compression of the spring would be.A. 0.12mB. 1.5mC. 0.5mD. 0.15m |
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Answer» Correct Answer - D From law of conservation of energy, `1/2mv^(2) = 1/2 xxkx^(2) rArr (0.5)(1.5)^(2) = 50x^(2)` `rArr x^(2) = (1.25/50) rArr x = 0.15` |
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