1.

A mass of 1 kg is suspended by a thread. It is (i) lifted up with an acceleration of 4.9mcdot s^(-2).

Answer»

`3:1`
`1:2`
`1:3`
`2:1`

Solution :Weight of the BODY = mg (DOWNWARDS)
Tension on the thread = T (upwards)
`THEREFORE` Resultant force acting on the body = T - mg (UPWARD)
If a si the upward acceleration then from F = ma we get.
T - mg = MAOR, T = m(g + a)


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