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A mass of 1 kg is suspended by a thread. It is (i) lifted up with an acceleration of 4.9mcdot s^(-2). |
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Answer» `3:1` Tension on the thread = T (upwards) `THEREFORE` Resultant force acting on the body = T - mg (UPWARD) If a si the upward acceleration then from F = ma we get. T - mg = MAOR, T = m(g + a) |
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