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A mass of 1 kg is suspended by a thread. It is lifted up with an acceleration 4.9m/s^(2) (ii) lowered with an acceleration of 4.9 mcdot s^(-2). The ratio of the tension on the thread is |
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Answer» Solution :Tension while lowering the MASS, `T_(2) = G - a = g - (g)/(2) = (g)/(2)` `therefore""T_(1) : T_(2) = (3g)/(2) : (g)/(2) = 3 : 1 ` Theoption A is correct. |
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