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A mass of 10 kg is dropped from a height of 50 cm. Find its(i) potential energy just before dropping.(ii) kinetic energy just on touching the ground,(iii) velocity with which it hits the ground. |
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Answer» Given, mass of the object, m = 10 kg, Height, h = 50 cm = 0.5 m (i) As potential energy is given by PE = mgh = 10 x 10 x 0.5 = 50 J (ii) From law of conservation of energy, Total energy of the ball just before dropping = total energy of the ball just on touching the ground ⇒ KE + PE of ball just before dropping = KE of ball just on touching the ground = KE= 50 J (iii) As , we know KE = 50J |
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