A mass of 10 kg is suspended by a rope of length 2.8m from a ceiling. A force of 98 N is applied at the midpoint of the rope as shown in figure. The angle which the rope makes with the vertical in equilibrium is

A mass of 10 kg is suspended by a rope of length 2.8m from a ceiling.

1.	A mass of 10 kg is suspended by a rope of length 2.8m from a ceiling. A force of 98 N is applied at the midpoint of the rope as shown in figure. The angle which the rope makes with the vertical in equilibrium is
Answer» `30^(@)` `60^(@)` `45^(@)` `90^(@)` Solution :`"ACCORDING to Lami.s theorem"(F_(1))/(SIN ALPHA)=(F_(2))/(sin beta)`