A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45∘ with the vertical. Then F equals:(Take g=10 ms−2 and the rope to be massless)

A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling

1.	A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45∘ with the vertical. Then F equals:(Take g=10 ms−2 and the rope to be massless)
Answer» A mass of $10 kg$ is suspended by a rope of length $4 m$ , from the ceiling. A force $F$ is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of $45^{\circ}$ with the vertical. Then $F$ equals: (Take $g = 10 {ms}^{- 2}$ and the rope to be massless)

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A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45∘ with the vertical. Then F equals:(Take g=10 ms−2 and the rope to be massless)

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