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A mass of `1kg` attached to one end of a string is first lifted up with an acceleration `4.9m//s^(2)` and then lowered with same acceleration What is the ratio of tension in string in two cases .

Answer» When mass is lifted up with acceleration `4.9m//s^(2)`
`T_(1) =m(g +a) =1 (9.8 +4.9) =14.7N`
When mass is lowered with same acceleration
`T_(2) =m(g -a) =1(9.8 -4.9) =4.9N`
`:. (T_(1))/(T_(2)) = (14.7)/(4.9) =3:1` .


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