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A mass of M kg is suspended by a weightless string the horizontal force that is required to displace it until the string makes an angle 45 degree with the initial vertical direction is |
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Answer» The work done by the force will be equal to the potential energy gained by the mass. Let L be the length of the string , F.d= MgL (1 -cos45 ) The horizontal displacement of the mass is d= L sin 45 F L sin45 = Mg L(1 - 45) F = Mg (√2 - 1) |
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