1.

A mass of M kg is suspended by a weightless string the horizontal force that is required to displace it until the string makes an angle 45 degree with the initial vertical direction is

Answer»

The work done by the force will be equal to the potential energy gained by the mass. 

Let L be the length of the string , 

F.d= MgL (1 -cos45 ) 

The horizontal displacement of the mass is d= L sin 45 

F L sin45 = Mg L(1 - 45) 

F = Mg (2 - 1)



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