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A mass of M kg is suspended by a weightless string.The horizontal force that is required to displace it until the string makes an angle of 45^° with the initial vertical direction is (a)Mg(\sqrt{2-1}) (b)Mg\sqrt{2+1} (c)Mg\sqrt2 (d)Mg/\sqrt2 ?? |
| Answer» A mass of M kg is suspended by a weightless string.The horizontal force that is required to displace it until the string makes an angle of 45^° with the initial vertical direction is (a)Mg(\sqrt{2-1}) (b)Mg\sqrt{2+1} (c)Mg\sqrt2 (d)Mg/\sqrt2 ?? | |