A massless rod PQ is hanging from two identical string AP and BQ of equal length. At point O a mass of m kg is hanging at length L5 from end P. If standing wave is set in string AP and BQ and the fundamental frequency of AP is equal to nth harmonic of BQ. Then the value of n is

A massless rod PQ is hanging from two identical string AP and BQ of eq

1.	A massless rod PQ is hanging from two identical string AP and BQ of equal length. At point O a mass of m kg is hanging at length L5 from end P. If standing wave is set in string AP and BQ and the fundamental frequency of AP is equal to nth harmonic of BQ. Then the value of n is
Answer» A massless rod $P Q$ is hanging from two identical string $A P$ and $B Q$ of equal length. At point $O$ a mass of $m kg$ is hanging at length $\frac{L}{5}$ from end $P$ . If standing wave is set in string $A P$ and $B Q$ and the fundamental frequency of $A P$ is equal to $n^{t h}$ harmonic of $B Q$ . Then the value of $n$ is

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A massless rod PQ is hanging from two identical string AP and BQ of equal length. At point O a mass of m kg is hanging at length L5 from end P. If standing wave is set in string AP and BQ and the fundamental frequency of AP is equal to nth harmonic of BQ. Then the value of n is

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