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A massless spool of inner radius `r` outer radius `R` is placed against a vertical wall and a titled split floor as shown. A light inextensible thread is tightly wound around the spool through which a mass `m` is hainging. There exists no friction at point `A`, while the coefficient of friction between the spool and point `B` is `mu`. The angle between the two surface is `theta` A. The magnitude of force on the spool at B in order ot maintain equilibrium is mg` sqrt(((r )/( R))^(2)+(1-( r)/( R))^(2)(1)/(tan^(2)theta))`B. The magnitude of force on the spool at B in order to maintain equilibrium is mg `(1-(r )/( R))(1)/( tan ^(2) theta)`C. The minimum value of `mu` for the system to ramain in equilibrium is `( cot theta)/((R//r)-1)`D. The minimum value of `mu` for the system to ramain in equilibrium is `( tan theta)/((R//r)-1)` |
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Answer» Correct Answer - A::D |
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