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A massless spring, having force constant k, oscillates with a frequency n when a mass m is suspended from it. The spring is cut into two equal halves and a mass 2m is suspended from one of the parts. The frequency of oscillation will now be…………. |
Answer» <html><body><p>n <br/>`nsqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`<br/>`(n)/(sqrt(2))`<br/>2n</p>Solution :`n=(1)/(2pi)sqrt((<a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>)/(m)),n.=(1)/(2)sqrt((2)/(2))=n`</body></html> | |