1.

A matchstick 5 cm long floats on water. The water film has a surface tension of 70 dyn/cm. A little comphor put on one side of stick reduces the surface tension there to 50 dyn/cm. The net force on the matchstick is (A) 4 dynes (B) 20 dynes (C) 100 dynes (D) 600 dynes.

Answer»

Correct Option is (C) 100 dynes

l = 5 cm

\(T_1 = 70\) dyne / cm

\(T = \frac{F}{l}\)

\(F_1 = T . l\)

\(F_1 = 5 \times 70\)

\(F_1 = 350\) dyne ............. \((F_1)\)

\(F_2 = T_2 .l\)

\(F_2 = 50 \times 5\)

\(F_2 = 250\) dyne .............. \((F_2)\)

Net. force = \(F_1 -F_2\) 

= 350 - 250

= 100 dynes

(C) 100 dynes



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