A material particle of mass m is revolving along a horizontal circular path of radius r under theinfluenece of the centripetal force = -(k)/(r^(2)) (k = constant ). What will be the total kinetic energy of the particle ?

A material particle of mass m is revolving along a horizontal circular

1.	A material particle of mass m is revolving along a horizontal circular path of radius r under theinfluenece of the centripetal force = -(k)/(r^(2)) (k = constant ). What will be the total kinetic energy of the particle ?
Answer» ANSWER :`(K)/(2R)`