1.

A maximum current point `0.5mA` can be passed through a galvanometer of resistance `20Omega` . The resistance to be connected in series to convert it in the voltmeter of range `0-5V` isA. `980Omega`B. `9980Omega`C. `990Omega`D. `9990Omega`

Answer» Correct Answer - 2
`R=((V)/(I_(g))-G)`


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