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A measured temperature on Fahrenheit scale is 200""^(@)F. What will this reading be on celsius scale ? |
Answer» <html><body><p>`40""^(@)C`<br/>`94""^(@)C`<br/>`93.3""^(@)C`<br/>`30""^(@)C`</p>Solution :There are only three <a href="https://interviewquestions.tuteehub.com/tag/scales-14900" style="font-weight:bold;" target="_blank" title="Click to know more about SCALES">SCALES</a> to measure temperature `""^(@)C, ""^(@)F` and . The K is the SI unit. <br/> The temperature on <a href="https://interviewquestions.tuteehub.com/tag/two-714195" style="font-weight:bold;" target="_blank" title="Click to know more about TWO">TWO</a> scales are related to each other by the following <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a>. <br/> `""^(@)F= 9/5 t""^(@)C+32` <br/> <a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> the values in above equation, <br/> `200-32= 9/5 t""^(@)C` <br/> `:.9/5 t""^(@)C= <a href="https://interviewquestions.tuteehub.com/tag/168-277726" style="font-weight:bold;" target="_blank" title="Click to know more about 168">168</a>`<br/> `:. t""^(@)C= (168xx5)/(9) = 93.3""^(@)C`</body></html> | |