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A medium has `n_v = 1.56, n_r=1.44`. Then its dispersive power is:A. `3//50`B. `6//25`C. `0.03`D. none of these

Answer» Correct Answer - D
`omega=(n_(v)-n_(r))/(((n_(v)+n_(r))/(2))-1)=(6)/(25)`


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