A metal block of area 0.10m^(2) is connected toa 0.010 kg mass via a string that passes over an ideal pulley (considered massless and frictionless), as in fig. A liquid with a film thickness of 0.30 mm is placed betwee the block and the table. When released the block moves to theright with a constant speed of 0.085ms^(-1). Find the coefficient of viscosity of the liquid.

A metal block of area 0.10m^(2) is connected toa 0.010 kg mass via a s

1.	A metal block of area 0.10m^(2) is connected toa 0.010 kg mass via a string that passes over an ideal pulley (considered massless and frictionless), as in fig. A liquid with a film thickness of 0.30 mm is placed betwee the block and the table. When released the block moves to theright with a constant speed of 0.085ms^(-1). Find the coefficient of viscosity of the liquid.
Answer» Solution :The metal block moves to the right because other tension in the string. The tension T is equal in MAGNITUDE to the WEIGHT of the suspended mass m. Thus the shear FORCE F is Shear STRESS on the fluit `F//A=(9.8xx10^(-2))/0.10` `="stain rate"=v/t=(0.085ms^(-1))/(0.3xx10^(-3)m)` `eta=("stress")/("strainrate")=3.45xx10^(-3)` Pas