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InterviewSolution
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A metal coil of area `5 xx 10^(-3)m^(2)`, number of turns 100 and resistance `0.5 Omega` is lying horizontally at the bottom of a vessel made of an insultating material. A uniform magnetic field passing vertically through the coil changes from 0 to 0.8t in 0.2 s. What is induced current (in ampere) flowing through the coil?A. 2AB. 3AC. 4AD. 5A |
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Answer» Correct Answer - C The magnetic flux `phi = NAB` `:.` The induced e.m.f. = `e = -(d phi)/(dt)` `:. |e| = |(d phi)/(dt)| = NA (dB)/(dt)` But (`dB)/(dt) = 0.8/0.2 = 4 T//s` `:. e = NA(dB)/(dt)=100 xx 5 xx 10^(-3) xx 4 :. e = 2 V` `:.` induced current `I = e/R = 2/0.5 = 4 A`. |
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