1.

A metal complex having composition Co(en)_(2)Cl_(2)Br has been isolated in two forms Aand B. (B) reacted with silver nitrate to give a white precipitate readily soluble in ammonium hydroxide . Whereas A gives a pale yellow precipitate. Write the formula of A and B, state the hybridization of Co in each and calculate their spin only magnetic moment.

Answer»

Solution :A metal complex having composition `Co(en)_(2)Cl_(2)Br` has been isolated in two forms `A` and `B`.
`(i) (B)` reacts with silver nitrate to give a white PRECIPITATE readily SOLUBLE in ammonium hydroxide . This shows (B) has `Cl^(OPLUS)` counter ion. Hence B is `[Co(en)_(2)ClBr]Cl` form.
`(ii)` (A) reacts with silver nitrate to give a pale yellow precipitate. This shows (A) has `Br^(oplus)` counter ion. Hence A is `[Co(en)_(2)Cl_(2)]Br`.
`(iii)` Formula of A and B
`A-[Co(en)_(2)Cl_(2)]Br`
`B-[Co(en)_(2)ClBr]Cl`
`(a) A-[Co(en)_(2)Cl_(2)]Br`
Electronic configuration of Co atom
Electronic configuration of `Co^(3+)` atom
Hybridisation and formation of
`[Co(en)_(2)Cl_(2)]Br` complex
`d^(2)sp^(3)` hybridisation
`en` is strong FIELD ligand
No unpaired electrons, hence it is diamagnetic
MAGNETIC moment,
`mu_(s)=sqrt(n(n+2))`
`n=0`
`mu_(s)=0`

`(b) A-[Co(en)_(2)ClBr]Cl`
Electronic configuration of Co atom
Electronic configuration of `Co^(3+)` atom
Hybridisation and formation of
`[Co(en)_(2)ClBr]Cl` complex
`d^(2)sp^(3)` hybridisation
`en` is strong field ligand
No unpaired electrons, hence it is diamagnetic
Magnetic moment,
`mu_(s)=0 :. {n=0`


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