1.

A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 rad s-1. If the horizontal component of the earth’s magnetic field is 0.2 x 10-4T, then emf developed between the two ends of the conductor is(A) 5μV(B) 50μV(C) 5mV(D) 50 mV

Answer»

The induced emf produced across the two ends of the conductor
e = \(\frac{1}{2}\) BlW = \(\frac{1}{2}\) × 0.2 × 10-4 × l× 5
= 5 ×10-5V = 50 µV
Answer is (B) 50μV



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