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a metal crystallizes with a face-centered cubic lattice.The edge of the unit cell is `408` pm. The diameter of the metal atom is :A. `288p m`B. `408 p m`C. `144p m`D. `204p m` |
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Answer» Correct Answer - 1 In a face -centered cubic lattice. the atom of the face centre is in touch with the other two atoms diagonally arranged at the corners. The length of the face diagonal is `sqrt(2)a` As all the three spheres along the face diagonal touch each other, the length of the body diagonal is also equal to `4r` where `r` is the radius of the sphere (atom). Therefore `4r=sqrt(2)a` or `r=(sqrt(2))/(4)a=(a)/(2sqrt(2))` the diameter `(d)` of the metal atom is `2r`.Therefore `d=2r=(a)/(sqrt(2))=(408p m)/(1.414)` `=288p m` |
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