A metal has a fcc lattice. The edge of the unit cell is 404 pm. The density of the metal is2.72 " g cm"^(-3) . The molar mass of the metal is( N_(A) , Avogardro's constant =6.02 xx 10^(23) mol^(-1))

A metal has a fcc lattice. The edge of the unit cell is 404 pm. The de

1.	A metal has a fcc lattice. The edge of the unit cell is 404 pm. The density of the metal is2.72 " g cm"^(-3) . The molar mass of the metal is( N_(A) , Avogardro's constant =6.02 xx 10^(23) mol^(-1))
Answer» ` 40g mol^(-1)` `30 g mol^(-1)` `27 g mol^(-1)` `20 g mol^(-1)` Solution :DENSITY , ` p= ( Z xx M)/(a^(3) xx N_(A) xx 10^(-30))` ` therefore2.72 = ( 4 xx M)/(( 404)^(3) xx ( 6.02 xx 10^(23)) xx 10^(-30))` `orM = ( 2.72 xx (404)^(3) xx 6.02 xx 10^(23) xx 10^(-30))/4` ` = 27 g mol^(-1)`