A metal has a fcc lattice. The edge of the unit cell is 404 pm. The density of the metal is2.72 " g cm"^(-3) . The molar mass of the metal is( N_(A) , Avogardro's constant =6.02 xx 10^(23) mol^(-1))

A metal has a fcc lattice. The edge of the unit cell is 404 pm. The de

1.	A metal has a fcc lattice. The edge of the unit cell is 404 pm. The density of the metal is2.72 " g cm"^(-3) . The molar mass of the metal is( N_(A) , Avogardro's constant =6.02 xx 10^(23) mol^(-1))
Answer» <html><body><p> ` 40g mol^(-1)` <br/>`30 g mol^(-1)` <br/>`27 g mol^(-1)`<br/>`20 g mol^(-1)` <br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> , ` p= ( Z xx M)/(a^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>) xx N_(A) xx 10^(-30))` <br/> ` therefore2.72 = ( 4 xx M)/(( 404)^(3) xx ( 6.02 xx 10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>)) xx 10^(-30))` <br/>`orM = ( 2.72 xx (404)^(3) xx 6.02 xx 10^(23) xx 10^(-30))/4` <br/>` = 27 g mol^(-1)`</body></html>