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A metal ion M^(n+) having d^(4) valence electrode configuration combines with three ligands to form a complex compound. Assuming Delta_(0)gtP. i) Draw the diagram assuming d-orbital splitting during the complex formation. ii) Write the electronic configuration of valence electrons of the metal M^(n+) ion in terms t_(2g) and e_(g). iii) What type of of hybrisation will M^(n+) ion have? iv) Name the type of isomerism exhibited by the complex. |
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Answer» SOLUTION :i) N/A ii) When `Delta_(0) gt P`, the electrons get paired up in the lower `t_(2g)` ORBITALS. The electronic configuration of `d^(4)` ion is: `t_(2g)^(2)e_(g)^(0)`. iii) The COMPLEX is octahedral since the didenate ligands are attached to the `M^(n+)` ion which is `d^(2)sp^(3)` hybridised. IV) The complex will exhibit optical isomerism. |
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