1.

A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. What is the K.E. of photo electrons

Answer»

`6.23xx10^(-20)` J
`6.25 xx 10^(-22)` J
`6.625xx10^(-18)` J
`6.625 xx10^(-19)` J

Solution :K.E `=1/2 mv^2 = 6.23xx10^(-20) J`


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