1.

A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. The value of X-intercept

Answer»

`9XX10^4 `Hz
`10.2xx10^5` Hz
`8.6xx10^5` Hz
`9xx10^(14)` Hz

Solution :`E = (hc)/(lambda) = 6.625 xx 10^(-19) J , KE =6.23xx10^(-20)J`
W`= E- KE= 6.002 xx 10^(-19)`
`hv_0 = 6.002xx10^(-19) impliesv_0 = 9.09xx10^(14) Hz`


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