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A metal is irradiated with a radiation of wavelength 300 nm. Then photo electrons found to have velocity of 3.7 xx 10^5 m/s. When a graph is drawn between K.E of photo electrons and frequency of radiation a straight line is obtained cutting X-axis. Difference between incident frequency and threshold frequency is |
Answer» <html><body><p>`9.4xx10^(13)` Hz<br/>`8.5xx10^(22)` Hz<br/>`9.4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)` Hz<br/>`8.4xx10^(10) Hz`</p>Solution :`upsilon - upsilon_0 =(6.625xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/19-280618" style="font-weight:bold;" target="_blank" title="Click to know more about 19">19</a>))/(6.625xx10^(13)) -9.09 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(14)`<br/> `=9.4xx10^(<a href="https://interviewquestions.tuteehub.com/tag/23-294845" style="font-weight:bold;" target="_blank" title="Click to know more about 23">23</a>) Hz`</body></html> | |