A metal is know to form fluoride `MF_(2)`. When `10A` of electricity is passed through a molten sat for `330sec, 1.95g` of metal is deposited. Find the atomic weight of M. what will be the quantity electricity required to deposit the same mass of `Cu` form `CuSO_(4)`?

A metal is know to form fluoride `MF_(2)`. When `10A` of electricity i

1.	A metal is know to form fluoride `MF_(2)`. When `10A` of electricity is passed through a molten sat for `330sec, 1.95g` of metal is deposited. Find the atomic weight of M. what will be the quantity electricity required to deposit the same mass of `Cu` form `CuSO_(4)`?
Answer» Correct Answer - `A = 114, Q = 5926, 8C` `M^(+2) + 2e^(-) rarr M rArr n_(e^(-)) = (2xx 1.95)/(M)` `rArr n_(M) = (1.95)/(M)` `=(2 xx 1.95)/(M) = (10 xx 330)/(96500)` `M = 114` `Cu^(+2) +2e^(-) rarr Cu` `n_(e^(-)) = (2 xx 1.95)/(63.5) n_(Cu) = (1.95)/(63.5)` `n_(E) = (Q)/(96500)` `Q = 5926.8C`

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A metal is know to form fluoride `MF_(2)`. When `10A` of electricity is passed through a molten sat for `330sec, 1.95g` of metal is deposited. Find the atomic weight of M. what will be the quantity electricity required to deposit the same mass of `Cu` form `CuSO_(4)`?

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