A metal is known to form fluoride `MF_(2)`. When `10` ampere electricity is passed through a molten salt for `330` sec, `1.95 g` metal is deposited. Find out the atomic weight of metal. What will be the quantity of charge required to deposit the same mass of `Cu` from `CuSO_(4)(aq.)`? (`At. wt.` of `Cu = 63.6`)

A metal is known to form fluoride `MF_(2)`. When `10` ampere electrici

1.	A metal is known to form fluoride `MF_(2)`. When `10` ampere electricity is passed through a molten salt for `330` sec, `1.95 g` metal is deposited. Find out the atomic weight of metal. What will be the quantity of charge required to deposit the same mass of `Cu` from `CuSO_(4)(aq.)`? (`At. wt.` of `Cu = 63.6`)
Answer» Eq. of metal `= (i.t)/(96500)` `(i = 10 "ampere", t = 330 sec.)` `(1.95)/(E) = (10 xx 330 sec)/(96500)` `E_("metal") = 57.0` `At. wt.` of metal `= 57.0 xx 2 = 114.0` metal is bivalent as salt is `MF_(2)` Also, if `w_(Cu) = 1.95 g`, then or `(1.95)/(63.6//2) = (i.t)/(96500)` `:. i.t = Q = 5917.45` coulomb

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