1.

A metal M forms an alum which contains the element potassium and is isomorphous with ordinary alum(K_2SO_4. Al_2(SO_4)_3 24H_2O) . If the alum of M contains 10.42% of M, then atomic weight of M is (at. mass of K= 39, O=16, S=32 and H=1):

Answer»

52
104
156
208

Solution :Since the alum is isomorphous with `K_2SO_4`
`Al_2(SO_4)_3.24H_2O ` its FORMULA is `K_2SO_4`.
`M_2(SO_4)_3 . 24 H_2O`
Molecular weight = 894 + 2M where M is the atomic weight of the metal
Now ` (2M)/(894 + 2M) xx 100 = 10.42 `
SOLVING M = 52


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