A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.A. 2E(y/x)B. xy/EC. E/yD. E/2(x/y)

A metal M of equivalent mass E forms an oxide of molecular formula `M_

1.	A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.A. 2E(y/x)B. xy/EC. E/yD. E/2(x/y)
Answer» Correct Answer - A If m is the atomic mass of the metal M, then 16y g of oxygen combine with xm g of the metal `:.` 8 g of oxygen will combine with metal `= (xm)/(16y)xx8 = (xm)/(2y)` `:. (xm)/(2y)=E` or `m=2E//(y//x)`

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A metal M of equivalent mass E forms an oxide of molecular formula `M_(x)O_(y)`. The atomic mass of the metal is given by the correct equation.A. 2E(y/x)B. xy/EC. E/yD. E/2(x/y)

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